X^2-67x+270=0

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Solution for X^2-67x+270=0 equation: 



X^2-67X+270=0

a = 1; b = -67; c = +270;
Δ = b2-4ac
Δ = -672-4·1·270
Δ = 3409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-\sqrt{3409}}{2*1}=\frac{67-\sqrt{3409}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+\sqrt{3409}}{2*1}=\frac{67+\sqrt{3409}}{2}
$

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